Average age of 8 sons of a family is 12 years. Average age of the sons together with their parents is 21 years. If the father is older than the mother - Quantitative Aptitude MCQ Competitive Exam 2026 | ExamTest.live

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Average age of 8 sons of a family is 12 years. Average age of the sons together with their parents is 21 years. If the father is older than the mother by 8 years, then the age of the mother is:

Solution & Step-by-step Explanation

Step 1: Calculate total age of the sons Sum of ages of 8 sons = 8 \times 12 = 96 years Step 2: Calculate total age of all family members Including the 2 parents, the total number of family members becomes 8 + 2 = 10 . Sum of ages of 10 members = 10 \times 21 = 210 years Step 3: Find the combined age of the parents Sum of ages of Father and Mother = 210 - 96 = 114 years Step 4: Determine individual ages Let the age of the mother be M . The father is 8 years older than the mother, so the father's age is M + 8 . M + (M + 8) = 114 2 M + 8 = 114 2 M = 106 M = \frac{106}{2} = 53 Thus, the age of the mother is 53 years.

Try it yourself before checking the explanation above.

Average age of 8 sons of a family is 12 years. Average age of the sons together with their parents is 21 years. If the father is older than the mother by 8 years, then the age of the mother is:

48 years

53 years

60 years

62 years

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