By what factors does the average velocity of a gaseous molecule increase when the temperature (in Kelvin) is doubled?

The average velocity ($v_{avg}$) of a gas molecule is given by:
$$v_{avg}=\sqrt{\frac{8RT}{\pi M}}$$
This shows that $v_{avg}\propto \sqrt{T}$.If the temperature is doubled ($T_2=2T_1$):
$$\frac{v_2}{v_1}=\sqrt{\frac{T_2}{T_1}}=\sqrt{2}\approx 1.414$$
Thus, the velocity increases by a factor of approximately $1.4$.