Choose the correct sequence of mathematical signs to replace the placeholders $\ast$ in order to balance the given equation.
$$(12\ast 7\ast 6)\ast 13\ast 6$$

Let's test the options to see which sequence of signs balances the expression:
The structure is: $((12\text{ sign1 }7\text{ sign2 }6)\text{ sign3 }13\text{ sign4 }6)$.
In all options, the last sign is '$=$ ', so the right-hand side (RHS) must evaluate to $6$.

Let's test Option B ($\times ,-,÷,=$):

* The equation becomes: $((12\times 7-6)÷13=6)$
* Following BODMAS rules, evaluate the inner parenthesis first:

$$12\times 7=84$$

$$84-6=78$$

* Now apply the next operator:

$$78÷13=6$$

Since $\text{LHS}=6$ and $\text{RHS}=6$, Option B correctly balances the equation.