Consider a standard geometric square with both of its internal major diagonals drawn completely from corner to corner. Count the total number of independent triangles formed inside this configuration.

Let the corners of the square be labeled $A,B,C,D$ in clockwise order, and let the central intersection point of the two diagonals be $O$.
Let us enumerate the individual triangles systematically:

1. Small Triangles (Single regions):
* $\Delta AOB$
* $\Delta BOC$
* $\Delta COD$
* $\Delta DOA$
*(Total small triangles = $4$)*

2. Large Triangles (Combining two adjacent small triangles along a diagonal line):
* $\Delta ABC$ (combining $AOB$ and $BOC$)
* $\Delta BCD$ (combining $BOC$ and $COD$)
* $\Delta CDA$ (combining $COD$ and $DOA$)
* $\Delta DAB$ (combining $DOA$ and $AOB$)
*(Total large triangles = $4$)*

$$\text{Total number of triangles}=4+4=8$$