Consider the 2-bit multiplexer (MUX) shown in the figure. For OUTPUT to be the XOR of C and D, the values for A₀, A₁, A₂, and A₃ are ________.

- AA₀ = 0, A₁ = 0, A₂ = 1, A₃ = 1
- BA 0 = 1, A 1 = 0, A 2 = 1, A 3 = 0
- CA 0 = 0, A 1 = 1, A 2 = 1, A 3 = 0
- DA 0 = 1, A 1 = 1, A 2 = 0, A 3 = 0
Solution & Step-by-step Explanation
The correct answer is option 3.
Concept:
The multiplexer abbreviated "MUX" or "MPX," is a combinational logic circuit that uses a control signal to switch one of the numerous input lines to a single common output line.
S S₀ are the select lines, I₁, I₂, I₃, and I₄ are the input lines and produce the output Y.

Y= (S₁' S₀' )I₀+( S₁'S₀)I1+(S₁ S₀' )I2 +( S₁S₀ )I3
Explanation:
Option 1: A 0 = 0, A 1 = 0, A 2 = 1, A 3 = 1
These input lines A 0 = 1, A 1 = 0, A 2 = 1, A 3 = 0, C and D are the select lines and produce the output
Y= (C' D' ) 0 +( C' D ) 0 +(C D' ) 1 +( CD) 1
Y=0+0+CD'+CD
Y=C(D'+D)
Y=C
Option 2: A 0 = 1, A 1 = 0, A 2 = 1, A 3 = 0
These input lines A0 = 0, A1 = 0, A2 = 1, A3 = 1, C and D are the select lines and produce the output
Y= (C'D') 1+( C' D ) 0+(C D' ) 1+( CD) 0
Y= C'D'+0+CD'+0
Y=D'(C'+C)
Y=D'
Option 3: A 0 = 0, A 1 = 1, A 2 = 1, A 3 = 0
These input lines A 0 = 0, A 1 = 1, A 2 = 1, A 3 = 0, C and D are the select lines and produce the output
Y= (C'D') 0+( C' D) 1+(CD') 1+( CD) 0
Y= 0 + C'D + CD' + 0
Y=C'D + CD'
Option 4: A 0 = 1, A 1 = 1, A 2 = 0, A 3 = 0
These input lines A 0 = 1, A 1 = 1, A 2 = 0, A 3 = 0, C and D are the select lines and produce the output
Y= (C'D') 1 + ( C' D ) 1 + (C D' ) 0 + ( CD) 0
Y= C'D '+ C'D + 0 + 0
Y=C'D '+ C'D
Y=C'(D' + D)
Y = C'
Hence the correct answer isA 0 = 0, A 1 = 1, A 2 = 1, A 3 = 0.
Concept:
The multiplexer abbreviated "MUX" or "MPX," is a combinational logic circuit that uses a control signal to switch one of the numerous input lines to a single common output line.
S S₀ are the select lines, I₁, I₂, I₃, and I₄ are the input lines and produce the output Y.

Y= (S₁' S₀' )I₀+( S₁'S₀)I1+(S₁ S₀' )I2 +( S₁S₀ )I3
Explanation:
Option 1: A 0 = 0, A 1 = 0, A 2 = 1, A 3 = 1
These input lines A 0 = 1, A 1 = 0, A 2 = 1, A 3 = 0, C and D are the select lines and produce the output
Y= (C' D' ) 0 +( C' D ) 0 +(C D' ) 1 +( CD) 1
Y=0+0+CD'+CD
Y=C(D'+D)
Y=C
Option 2: A 0 = 1, A 1 = 0, A 2 = 1, A 3 = 0
These input lines A0 = 0, A1 = 0, A2 = 1, A3 = 1, C and D are the select lines and produce the output
Y= (C'D') 1+( C' D ) 0+(C D' ) 1+( CD) 0
Y= C'D'+0+CD'+0
Y=D'(C'+C)
Y=D'
Option 3: A 0 = 0, A 1 = 1, A 2 = 1, A 3 = 0
These input lines A 0 = 0, A 1 = 1, A 2 = 1, A 3 = 0, C and D are the select lines and produce the output
Y= (C'D') 0+( C' D) 1+(CD') 1+( CD) 0
Y= 0 + C'D + CD' + 0
Y=C'D + CD'
Option 4: A 0 = 1, A 1 = 1, A 2 = 0, A 3 = 0
These input lines A 0 = 1, A 1 = 1, A 2 = 0, A 3 = 0, C and D are the select lines and produce the output
Y= (C'D') 1 + ( C' D ) 1 + (C D' ) 0 + ( CD) 0
Y= C'D '+ C'D + 0 + 0
Y=C'D '+ C'D
Y=C'(D' + D)
Y = C'
Hence the correct answer isA 0 = 0, A 1 = 1, A 2 = 1, A 3 = 0.