Consider the constraints:$5x+y\le 100$$x+y\le 60$$x\ge 0,y\ge 0$ Solving by graphical method, which point among the following will not form a boundary/corner point of the feasible region?

1. Boundary of $x\ge 0,y\ge 0$ are the axes. Corner point: $(0,0)$.2. Line $5x+y=100$: Intercepts are $(20,0)$ and $(0,100)$.3. Line $x+y=60$: Intercepts are $(60,0)$ and $(0,60)$.4. Intersection of $5x+y=100$ and $x+y=60$:Subtracting the equations: $4x=40⟹x=10$.Then $10+y=60⟹y=50$. Point: $(10,50)$.Feasible region points check:For $(60,0)$: $5(60)+0=300\nleqq 100$. Out of region.The corner points of the region are $(0,0),(20,0),(10,50),(0,60)$.Point $(60,0)$ is outside the feasible region defined by $5x+y\le 100$.