Consider the following reaction: xMnO_4^- + yC_2O_4^2- + zH^+ → xMn^2+ + 2yCO_2 + z/2H_2O The values of x, y and z in the reaction are, respectively: - Chemistry MCQ JEE Main 2026 | ExamTest.live

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Consider the following reaction: x MnO_{4}^{-} + y C_{2} O_{4}^{2 -} + z H^{+} \to x Mn^{2 +} + 2 y CO_{2} + \frac{z}{2} H_{2} O The values of x, y and z in the reaction are, respectively:

Solution & Step-by-step Explanation

Balancing via the ion-electron method:Oxidation half: C_{2} O_{4}^{2 -} \to 2 CO_{2} + 2 e^{-} Reduction half: MnO_{4}^{-} + 8 H^{+} + 5 e^{-} \to Mn^{2 +} + 4 H_{2} O Multiplying eq(1) by 5 and eq(2) by 2 : 2 MnO_{4}^{-} + 5 C_{2} O_{4}^{2 -} + 16 H^{+} \to 2 Mn^{2 +} + 10 CO_{2} + 8 H_{2} O Thus, x = 2, y = 5, z = 16 .

Try it yourself before checking the explanation above.

Consider the following reaction: x MnO_{4}^{-} + y C_{2} O_{4}^{2 -} + z H^{+} \to x Mn^{2 +} + 2 y CO_{2} + \frac{z}{2} H_{2} O The values of x, y and z in the reaction are, respectively:

2, 5 and 8

2, 5 and 16

5, 2 and 8

5, 2 and 16

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