Consider the following statements:
(i) Six flats on a floor in two rows facing North and South are allotted to $P$, $Q$, $R$, $S$, $T$ and $U$.
(ii) $Q$ gets a North facing flat and is not next to $S$.
(iii) $S$ and $U$ get diagonally opposite flats.
(iv) $R$, next to $U$, gets a South facing flat and $T$ gets a North facing flat.

Which of the following combinations get South facing flats?

Let there be two parallel rows of 3 flats each:
* South-facing row (facing North direction)
* North-facing row (facing South direction)
* Let's define the rows as Row 1 (South-facing, looking downwards/North towards the other row) and Row 2 (North-facing). Let's use standard facing layout where Top Row faces South, Bottom Row faces North.

From the statements:

1. $Q$ gets a North-facing flat $⟹Q$ is in the bottom row.
2. $T$ gets a North-facing flat $⟹T$ is in the bottom row.
3. $R$ gets a South-facing flat $⟹R$ is in the top row.
4. $R$ is next to $U⟹U$ must be in the top row (South-facing).
5. $S$ and $U$ are diagonally opposite. Since $U$ is in the top row, $S$ must be in the bottom row (North-facing).
6. Thus, the bottom row (North-facing flats) contains $Q$, $T$, and $S$.
7. The remaining person, $P$, must be in the top row (South-facing flats).

Therefore, the group of people getting South-facing flats are $U$, $R$, and $P$.