Consider the ground state of a $\text{Cr}$ atom ($Z=24$). The number of electrons with azimuthal quantum numbers $l=1$ and $l=2$ are respectively:

The ground state electronic configuration of Chromium ($Z=24$) is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{1}3d^5$.Azimuthal quantum number $l=1$ refers to $p$ orbitals. The electrons are in $2p^6$ and $3p^6$, totaling $6+6=12$ electrons.Azimuthal quantum number $l=2$ refers to $d$ orbitals. The electrons are in $3d^5$, totaling $5$ electrons.
Thus, the counts are $12$ and $5$.