Consider the sequence of dates given below:
6 | 12 | 71, 2 | 1 | 72, 29 | 1 | 72, 25 | 2 | 72,...
What is the next term of the sequence?
- A22 | 3 | 72
- B23 | 3 | 72
- C24 | 3 | 72
- D25 | 3 | 72
Solution & Step-by-step Explanation
Let's find the number of days separating successive terms in the series:
1. From 6 Dec 1971 to 2 Jan 1972: December has 31 days. .
2. From 2 Jan 1972 to 29 Jan 1972: .
3. From 29 Jan 1972 to 25 Feb 1972: January has 31 days. .
The rule of the sequence is to consistently add days to the current date.
Note that the year is a leap year, meaning February 1972 has days.
Adding days to 25 Feb 1972:
* Days remaining in February = .
* Days left to add in March = .
Thus, the next date is 23rd March 1972, which is formatted as
1. From 6 Dec 1971 to 2 Jan 1972: December has 31 days. .
2. From 2 Jan 1972 to 29 Jan 1972: .
3. From 29 Jan 1972 to 25 Feb 1972: January has 31 days. .
The rule of the sequence is to consistently add days to the current date.
Note that the year is a leap year, meaning February 1972 has days.
Adding days to 25 Feb 1972:
* Days remaining in February = .
* Days left to add in March = .
Thus, the next date is 23rd March 1972, which is formatted as
23 | 3 | 72.