Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL . The molality of the solution is: - Chemistry MCQ AIEEE 2006 2026 | ExamTest.live

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Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL . The molality of the solution is:

Solution & Step-by-step Explanation

1. Assume 1 L of solution.2. Mass of solution = 1000 mL \times 1.02 g/mL = 1020 g .3. Moles of solute = 2.05 mol .4. Mass of solute = 2.05 \times 60 = 123 g .5. Mass of solvent = Mass of solution - Mass of solute = 1020 - 123 = 897 g = 0.897 kg .6. Molality (m) = moles of solute / mass of solvent in kg . m = \frac{2.05}{0.897} \approx 2.285 mol/kg

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Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL . The molality of the solution is:

1.14 mol kg^{- 1}

3.28 mol kg^{- 1}

2.28 mol kg^{- 1}

0.44 mol kg^{- 1}

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