During the previous year, the price of an electronic item increased by 10\% , and this year, the price of the

Question

During the previous year, the price of an electronic item increased by 10\% , and this year, the price of the same item decreased by 10\% . If the price of the electronic item at present is ₹66,000 , then what was the price of the discussed electronic item in the beginning of the previous year? (Rou

Accepted Answer

Let the initial price of the item in the beginning of the previous year be

x

. The price increases by

10%

in the first year:

Price after 1st year = x \times (1 + \frac{10}{100}) = 1.1 x

The price decreases by

10%

in the second year:

Present Price = 1.1 x \times (1 - \frac{10}{100}) = 1.1 x \times 0.9 = 0.99 x

We are given that the present price is

₹66, 000

:

0.99 x = 66, 000

x = \frac{66 , 000}{0.99} = \frac{6 , 600 , 000}{99}

Simplifying by dividing numerator and denominator by

33

:

x = \frac{200 , 000}{3} \approx 66, 666.666...

Rounding off to one decimal place, we get

₹66, 666.7

.

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