Eight labourers working 10 hours a day completed a work in 18 days. If only 5 labourers are working, then in how many hours a day should they work to finish the work in 24 days?
- A9 hours
- B8 hours
- C10 hours
- D12 hours
Solution & Step-by-step Explanation
We can use the work-equivalence formula:
M
1
×D
1
×H
1
=M
2
×D
2
×H
2
Where:
M
1
=8, D
1
=18, H
1
=10
M
2
=5, D
2
=24, H
2
=hours per day required
Substituting the values:
8×18×10=5×24×H
2
1440=120×H
2
H
2
=
120
1440
=12hours
M
1
×D
1
×H
1
=M
2
×D
2
×H
2
Where:
M
1
=8, D
1
=18, H
1
=10
M
2
=5, D
2
=24, H
2
=hours per day required
Substituting the values:
8×18×10=5×24×H
2
1440=120×H
2
H
2
=
120
1440
=12hours