Equal masses of H_2, O_2 and methane have been taken in a container of volume V at temperature 27^ in identical conditions. The ratio of the volumes o - Chemistry MCQ Chemistry | ExamTest.live

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Equal masses of H_{2}, O_{2} and methane have been taken in a container of volume V at temperature 2 7^{\circ} C in identical conditions. The ratio of the volumes of gases H_{2} : O_{2} : methane would be:

A $8 : 16 : 1$
B $16 : 8 : 1$
C $16 : 1 : 2$
D $8 : 1 : 2$

Solution & Step-by-step Explanation

According to Avogadro's Law, at same T and P, volume ratio is equal to the mole ratio.Let mass of each gas be w .Moles of H_{2} = w /2 Moles of O_{2} = w /32 Moles of CH_{4} = w /16 Ratio of moles: \frac{w}{2} : \frac{w}{32} : \frac{w}{16} \frac{1}{2} : \frac{1}{32} : \frac{1}{16} Multiply by 32: 16 : 1 : 2 .

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Equal masses of H_{2}, O_{2} and methane have been taken in a container of volume V at temperature 2 7^{\circ} C in identical conditions. The ratio of the volumes of gases H_{2} : O_{2} : methane would be:

8 : 16 : 1

16 : 8 : 1

16 : 1 : 2

8 : 1 : 2

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Gaseous State Avogadro's Law

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Equal masses of $H_{2}, O_{2}$ and methane have been taken in a container of volume $V$ at temperature $2 7^{\circ} C$ in identical conditions. The ratio of the volumes of gases $H_{2} : O_{2} : methane$ would be:

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Equal masses of H2​,O2​ and methane have been taken in a container of volume V at temperature 27∘C in identical conditions. The ratio of the volumes of gases H2​:O2​:methane would be:

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Equal masses of $H_{2}, O_{2}$ and methane have been taken in a container of volume $V$ at temperature $2 7^{\circ} C$ in identical conditions. The ratio of the volumes of gases $H_{2} : O_{2} : methane$ would be: