Evaluate the expression:
$$\frac{(1024{)}^{n/5}\times 4^{2n+1}}{16^n\times 4^{n-1}}$$

Let's convert all terms to base 4 to simplify the fraction step-by-step:
1. Express 1024 and 16 as powers of 4:

$$1024=4^5$$

$$16=4^2$$

2. Substitute these base values back into the expression:

$$\text{Numerator}=(4^5{)}^{n/5}\times 4^{2n+1}=4^n\times 4^{2n+1}=4^{n+2n+1}=4^{3n+1}$$

$$\text{Denominator}=(4^2{)}^n\times 4^{n-1}=4^{2n}\times 4^{n-1}=4^{2n+n-1}=4^{3n-1}$$

3. Divide the numerator by the denominator:

$$\frac{4^{3n+1}}{4^{3n-1}}=4^{(3n+1)-(3n-1)}=4^2=16$$