Find out the odd word/letters/number/number pair from the given alternatives.

Let's convert the letter pairs into their numerical alphabetical positions:
BC→B=2,C=3⟹2×3=6

IF→I=9,F=6⟹9×6=54

CL→C=3,L=12⟹3×12=36

GH→G=7,H=8⟹7×8=56

Let's look closely at the product or properties:
Alternatively, check the step/difference between the positions:

BC→3−2=1

IF→6−9=−3

CL→12−3=9

GH→8−7=1

Let us analyze the position values directly:

B=2, C=3 (both consecutive numbers)

G=7, H=8 (both consecutive numbers)

I=9, F=6 (both are multiples of 3)

C=3, L=12 (both are multiples of 3)

Let's test another logic based on the alphabetical order:
In pairs BC and GH, the letters are in increasing alphabetical order (BF (decreasing).

Let's analyze the sum of values:

B+C=2+3=5

I+F=9+6=15

C+L=3+12=15

G+H=7+8=15

Notice that for options B, C, and D, the sum of the numerical positions of the letters is exactly 15.
For option A (BC), the sum is 5.
Therefore, BC is the odd pair out.