Find the $6\text{th}$ term in the following series:
$$a{b}^2+b{c}^2+c{d}^2+d{e}^2+\dots$$

Let's observe the structure of successive terms in the series:
* $1\text{st term}=a{b}^2$
* $2\text{nd term}=b{c}^2$
* $3\text{rd term}=c{d}^2$
* $4\text{th term}=d{e}^2$

The pattern shows that each term consists of an alphabetical letter followed by the next chronological letter raised to the power of $2$. Following this rule:

* $5\text{th term}=e{f}^2$
* $6\text{th term}=f{g}^2$