Find the area of a minor sector of a circle whose circumference is $88\text{cm}$ and the length of its minor arc is $22\text{cm}$ (use $\pi =\frac{22}{7}$).

**Step 1: Find the radius ($r$) of the circle**
The formula for circumference is:

$$2\pi r=88\text{cm}$$

$$2\times \frac{22}{7}\times r=88$$

$$\frac{44}{7}r=88⟹r=\frac{88\times 7}{44}=14\text{cm}$$

Step 2: Calculate the area of the minor sector
The relationship between the area of a sector ($A$), the arc length ($l$), and the radius ($r$) is given by:

$$A=\frac{1}{2}\times l\times r$$

Given that the minor arc length $l=22\text{cm}$:

$$A=\frac{1}{2}\times 22\times 14=11\times 14=154{\text{cm}}^2$$