Find the area of a triangle with vertices at points A(1, 1) , B(6, 0) , and C(3, 2) . - Mathematics MCQ Mathematics Mock Test - 4 2026 | ExamTest.live

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Find the area of a triangle with vertices at points A (1, 1), B (6, 0), and C (3, 2) .

Solution & Step-by-step Explanation

Area of a triangle with vertices (x_{1}, y_{1}), (x_{2}, y_{2}), and (x_{3}, y_{3}) is: Area = \frac{1}{2} ∣ x_{1} (y_{2} - y_{3}) + x_{2} (y_{3} - y_{1}) + x_{3} (y_{1} - y_{2}) ∣ Substitute coordinates: (1, 1), (6, 0), (3, 2) $ Area = \frac{1}{2} ∣1 (0 - 2) + 6 (2 - 1) + 3 (1 - 0) ∣ $ Area = \frac{1}{2} ∣1 (- 2) + 6 (1) + 3 (1) ∣ Area = \frac{1}{2} ∣ - 2 + 6 + 3∣ Area = \frac{1}{2} ∣7∣ = \frac{7}{2}

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Find the area of a triangle with vertices at points A (1, 1), B (6, 0), and C (3, 2) .

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