Find the compound amount and compound interest for ₹$10,000$ at $3\%$ interest per annum in $2\text{years}$.

Given:
* Principal ($P$) = ₹$10,000$
* Rate ($R$) = $3\%$ per annum
* Time ($n$) = $2\text{years}$

The formula for compound amount ($A$) is:

$$A=P{\left(1+\frac{R}{100}\right)}^n$$

Substitute the given values:

$$A=10000{\left(1+\frac{3}{100}\right)}^2$$

$$A=10000{\left(\frac{103}{100}\right)}^2$$

$$A=10000\times \frac{10609}{10000}$$

$$A=₹10,609$$

Now, find the Compound Interest ($\text{CI}$):

$$\text{CI}=A-P$$

$$\text{CI}=10609-10000=₹609$$

Therefore, the compound amount is ₹$10,609$ and the compound interest is ₹$609$.