Find the next term in the given series:
$$\text{AZ3, HX8, OV15, VT24, CR35, \_\_\_\_\_}$$

Let's split each term into three components: first letter, second letter, and number.
1. First letters: A, H, O, V, C, ...
* A (+7) $\to$ H
* H (+7) $\to$ O
* O (+7) $\to$ V
* V (+7) $\to$ C ($22+7=29\equiv 3=\text{C}$)
* C (+7) $\to$ J ($3+7=10=\text{J}$)

2. Second letters: Z, X, V, T, R, ...
* Z (-2) $\to$ X
* X (-2) $\to$ V
* V (-2) $\to$ T
* T (-2) $\to$ R
* R (-2) $\to$ P ($18-2=16=\text{P}$)

3. Numbers: 3, 8, 15, 24, 35, ...
Let's check the differences between numbers:
* $8-3=5$
* $15-8=7$
* $24-15=9$
* $35-24=11$
The differences are increasing consecutive odd numbers ($5,7,9,11$). The next difference must be $13$:
* $\text{Next number}=35+13=48$
(Alternatively, notice the pattern is $n^2-1$: $2^2-1=3$, $3^2-1=8$, $4^2-1=15$, $5^2-1=24$, $6^2-1=35$, so next is $7^2-1=48$).

Combining all components together, the next term is JP48.