Find the number of triangles in the figure.

Let's count the triangles systematically in the given geometrical figure:
1. Inside the central square box:
The square is divided into 4 quarters by a vertical line and a horizontal line, along with diagonals inside.
* Smallest individual triangles inside the square = $4$ triangles.
* Triangles formed by combining two small triangles (halves of the inner square) = $4$ triangles.
So, the inner square section contains $4+4=8$ triangles.

2. Outer large square corner triangles:
The inner square is placed inside a rotated larger square (diamond shape), creating triangles at the corners:
* Top corner triangle = $1$
* Bottom corner triangle = $1$
* Left corner triangle = $1$
* Right corner triangle = $1$
Total outer corner triangles = $4$ triangles.

3. Total Triangles = $8\text{ (inner)}+4\text{ (outer)}=12$ triangles.