Find the smallest non-zero value of k so that the 7-digit number 48397k5 is divisible by 9.
- A2
- B5
- C4
- D9
Solution & Step-by-step Explanation
A number is divisible by 9 if the sum of its digits is divisible by 9.
Let's find the sum of the digits of 48397k5:
Sum=4+8+3+9+7+k+5=36+k
For (36+k) to be divisible by 9, k must be a multiple of 9 or 0 because 36 is already perfectly divisible by 9 (36=9×4).
Since the question asks for the smallest non-zero value, we choose:
k=9
Let's find the sum of the digits of 48397k5:
Sum=4+8+3+9+7+k+5=36+k
For (36+k) to be divisible by 9, k must be a multiple of 9 or 0 because 36 is already perfectly divisible by 9 (36=9×4).
Since the question asks for the smallest non-zero value, we choose:
k=9