Find the value of $0.682^2-0.318^2$.

We can apply the algebraic identity for the difference of squares:
$$a^2-b^2=(a-b)(a+b)$$

Here, $a=0.682$ and $b=0.318$.
$$a-b=0.682-0.318=0.364$$
$$a+b=0.682+0.318=1.000$$

Substituting these values back into the identity:
$$0.682^2-0.318^2=(0.364)\times (1.000)=0.364$$