For a continuous random variable $X$ distributed in the interval $[0,10]$, the probability $P(X=2)$ is:

In the case of any continuous random variable, the probability of the variable taking on an exact, specific value is always zero. This is because probability is calculated as the area under the PDF curve ($P(a\le X\le b)={\int }_a^{b}f(x)dx$). For a single point, the width of the interval is zero, thus the area (integral) is zero.
$$P(X=2)={\int }_2^{2}f(x)dx=0$$