For a particle in uniform circular motion the acceleration a at a point P(R, θ) on the circle of radius R is (here θ is measured from the x -axis): - Physics MCQ AIEEE 2026 | ExamTest.live

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For a particle in uniform circular motion the acceleration a at a point P (R, θ) on the circle of radius R is (here θ is measured from the x -axis):

Solution & Step-by-step Explanation

In uniform circular motion, the acceleration is strictly centripetal, directed towards the center (0, 0) from point P (R cos θ, R sin θ) .The direction vector from P to the center is (- cos θ \hat{i} - sin θ \hat{j}) .Magnitude of centripetal acceleration is a_{c} = \frac{v ^{2}}{R} .Vector form: a = \frac{v ^{2}}{R} (- cos θ \hat{i} - sin θ \hat{j}) .

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For a particle in uniform circular motion the acceleration a at a point P (R, θ) on the circle of radius R is (here θ is measured from the x -axis):

- \frac{v ^{2}}{R} cos θ \hat{i} + \frac{v ^{2}}{R} sin θ \hat{j}

- \frac{v ^{2}}{R} sin θ \hat{i} + \frac{v ^{2}}{R} cos θ \hat{j}

- \frac{v ^{2}}{R} cos θ \hat{i} - \frac{v ^{2}}{R} sin θ \hat{j}

\frac{v ^{2}}{R} \hat{i} + \frac{v ^{2}}{R} \hat{j}

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