For a particular reversible reaction at temperature T , H and S were found to be both +ve . If T_e is the temperature at equilibrium, the reaction wou - Chemistry MCQ AIEEE 2026 | ExamTest.live

mediumMCQAIEEE2026Chemistry

1 mark

For a particular reversible reaction at temperature T, Δ H and Δ S were found to be both + ve . If T_{e} is the temperature at equilibrium, the reaction would be spontaneous when:

Solution & Step-by-step Explanation

At equilibrium, Δ G = 0 = Δ H - T_{e} Δ S ⟹ T_{e} = \frac{Δ H}{Δ S} .For spontaneity, Δ G < 0 : Δ H - T Δ S < 0 Δ H < T Δ S \frac{Δ H}{Δ S} < T T_{e} < T So, the reaction is spontaneous when T > T_{e} .

Try it yourself before checking the explanation above.

For a particular reversible reaction at temperature T, Δ H and Δ S were found to be both + ve . If T_{e} is the temperature at equilibrium, the reaction would be spontaneous when:

T_{e} > T

T > T_{e}

T_{e} is 5 times T

T = T_{e}

Practice with timed mock tests and track your performance across Chemistry.