HomeTestsSearchRankProfile
mediumMCQPhysicsPhysics
8 attempts0% success rate1 mark (−0.25)

For a satellite moving in an orbit around the earth, the ratio of kinetic energy to potential energy is :

  1. A
    4
  2. B
    1/2
  3. C
    1/√2
  4. D
    1

Solution & Step-by-step Explanation

For a satellite in orbit around the Earth, the gravitational potential energy (U) is given by U = -GMm/r, where G is the gravitational constant, M is the mass of the Earth, m is the mass of the satellite, and r is the radius of the orbit. The kinetic energy (K) of the satellite is given by K = (1/2)mv^2, where v is the velocity of the satellite. The velocity of a satellite in a circular orbit is given by v = √(GM/r). Substituting this into the expression for kinetic energy gives K = (1/2)m * (GM/r) = GMm / (2r). The ratio of kinetic energy to potential energy is thus K/U = (GMm / (2r)) / (-GMm/r) = -1/2.

Practice this question

Try it yourself before checking the explanation above.

For a satellite moving in an orbit around the earth, the ratio of kinetic energy to potential energy is :
A
4
B
1/2
C
1/√2
D
1

Share This Question

Related Questions

mediumMCQ

Consider a water tank as shown in the figure. It has one wall at x = L and is very wide in the z direction. When filled with a liquid of surface tension S and density ρ , the liquid surface makes an angle θ_0 ( θ_0 1 ) with the x -axis at x = L . If y(x) is the height of the surface, then the equation for y(x) is:(Take θ(x) ≈ θ(x) ≈ θ(x) = dy/dx and g as acceleration due to gravity) ![image](https://pub-7faa453bd1ec4bf0a04cc031c6f058de.r2.dev/images/e48999a7-2b29-4d5c-be16-ae2fd5fbcea5.png)

mediumMCQ

A microscope has an objective of focal length 2 cm , eyepiece of focal length 4 cm and the tube length of 40 cm . If the distance of distinct vision of eye is 25 cm , the magnification in the microscope is:

mediumMCQ

An electron (mass 9 × 10^-31 kg and charge 1.6 × 10^-19 C ) moving with speed c/100 ( c = speed of light) is injected into a magnetic field B of magnitude 9 × 10^-4 T perpendicular to its direction of motion. We wish to apply a uniform electric field E together with the magnetic field so that the electron does not deflect from its path. Then (speed of light c = 3 × 10^8 ms^-1 ):

mediumMCQ

There are two inclined surfaces of equal length ( L ) and same angle of inclination 45^ with the horizontal. One of them is rough and the other is perfectly smooth. A given body takes 2 times as much time to slide down on rough surface than on the smooth surface. The coefficient of kinetic friction ( μ_k ) between the object and the rough surface is close to:

mediumMCQ

The kinetic energies of two similar cars A and B are 100 J and 225 J respectively. On applying breaks, car A stops after 1000 m and car B stops after 1500 m . If F_A and F_B are the forces applied by the breaks on cars A and B, respectively, then the ratio F_A/F_B is:

mediumMCQ

The current passing through the battery in the given circuit is: ![image](https://pub-7faa453bd1ec4bf0a04cc031c6f058de.r2.dev/images/5a163a0c-22d0-4a96-bcd2-b569518db0a4.png)

Ready for a Full Test?

Practice with timed mock tests and track your performance across Physics.

Discussion