For the reaction, $2Cl(g)\to C{l}_2(g)$, the correct option is:

${\Delta }_{r}H$: Bond formation occurs ($2Cl\to C{l}_2$), which is an exothermic process. So, ${\Delta }_{r}H<0$.${\Delta }_{r}S$: Number of gaseous moles decreases from $2$ to $1$, leading to less randomness. So, ${\Delta }_{r}S<0$.