For the reaction: 2NO_2(g) leftharpoons 2NO(g) + O_2(g) , it is found that at 184^ , K_c = 1.8 × 10^-6 . When K_p and K_c are compared at this tempera - Chemistry MCQ AIEEE 2026 | ExamTest.live

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For the reaction: 2 NO_{2} (g) ⇌ 2 NO (g) + O_{2} (g), it is found that at 18 4^{\circ} C, K_{c} = 1.8 \times 1 0^{- 6} . When K_{p} and K_{c} are compared at this temperature, it is found that:

Solution & Step-by-step Explanation

The relationship is K_{p} = K_{c} (RT)^{Δ n_{g}} .For the reaction: 2 NO_{2} (g) ⇌ 2 NO (g) + O_{2} (g) Δ n_{g} = (2 + 1) - 2 = + 1 . K_{p} = K_{c} (RT)^{1} At 18 4^{\circ} C (457 K), RT = 0.0821 \times 457 \approx 37.5, which is > 1 .Since Δ n_{g} > 0 and RT > 1, K_{p} > K_{c} .

Try it yourself before checking the explanation above.

For the reaction: 2 NO_{2} (g) ⇌ 2 NO (g) + O_{2} (g), it is found that at 18 4^{\circ} C, K_{c} = 1.8 \times 1 0^{- 6} . When K_{p} and K_{c} are compared at this temperature, it is found that:

K_{p} is greater than K_{c}

K_{p} is less than K_{c}

K_{p} = K_{c}

The relationship depends upon the total gas pressure

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