For the reaction, CO(g) + Cl_2(g) leftharpoons COCl_2(g) the K_p/K_c is equal to: - Chemistry MCQ AIEEE 2004 2026 | ExamTest.live

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For the reaction, CO (g) + Cl_{2} (g) ⇌ COCl_{2} (g) the \frac{K _{p}}{K _{c}} is equal to:

Solution & Step-by-step Explanation

The relationship is K_{p} = K_{c} (RT)^{Δ n} . For the reaction CO (g) + Cl_{2} (g) ⇌ COCl_{2} (g) : Δ n = (moles of gaseous product) - (moles of gaseous reactant) = 1 - (1 + 1) = - 1 . \frac{K _{p}}{K _{c}} = (RT)^{- 1} = \frac{1}{RT} .

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For the reaction, CO (g) + Cl_{2} (g) ⇌ COCl_{2} (g) the \frac{K _{p}}{K _{c}} is equal to:

\frac{1}{RT}

1.0

RT

RT

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