Four options have been given out of which three are alike in some manner, while one is different. Choose the odd one.
- A51-24
- B32-41
- C36-59
- D61-34
Solution & Step-by-step Explanation
Let's calculate the absolute difference between the two numbers in each option:
Option A: ∣51−24∣=27
Option B: ∣32−41∣=9
Option C: ∣36−59∣=23
Option D: ∣61−34∣=27
We see that differences don't show a 3-to-1 uniformity except that A and D give 27. Let's look at another pattern: the sum of the digits.
Option A: 51−24→(5+1)=6 and (2+4)=6. Both digit sums are equal (6=6).
Option B: 32−41→(3+2)=5 and (4+1)=5. Both digit sums are equal (5=5).
Option D: 61−34→(6+1)=7 and (3+4)=7. Both digit sums are equal (7=7).
Option C: 36−59→(3+6)=9 and (5+9)=14. The digit sums are not equal (9
=14).
Hence, Option C is the odd one out.
Option A: ∣51−24∣=27
Option B: ∣32−41∣=9
Option C: ∣36−59∣=23
Option D: ∣61−34∣=27
We see that differences don't show a 3-to-1 uniformity except that A and D give 27. Let's look at another pattern: the sum of the digits.
Option A: 51−24→(5+1)=6 and (2+4)=6. Both digit sums are equal (6=6).
Option B: 32−41→(3+2)=5 and (4+1)=5. Both digit sums are equal (5=5).
Option D: 61−34→(6+1)=7 and (3+4)=7. Both digit sums are equal (7=7).
Option C: 36−59→(3+6)=9 and (5+9)=14. The digit sums are not equal (9
=14).
Hence, Option C is the odd one out.