Given below are two statements:Statement I: Aniline does not undergo Friedel-Crafts alkylation.Statement II: Aniline cannot be prepared through Gabriel phthalimide synthesis.

1. Statement I: Aniline is a Lewis base, and ${\text{AlCl}}_3$ used in Friedel-Crafts is a Lewis acid. They react to form a salt ($-{\text{NH}}_2^{+}{\text{-AlCl}}_3^{-}$). The positively charged nitrogen exerts a strong deactivating effect on the ring, preventing the reaction. (Correct)2. Statement II: Gabriel phthalimide synthesis involves an $S_{N}2$ reaction with an alkyl halide. Aryl halides (like chlorobenzene used for aniline) do not undergo $S_{N}2$ readily due to partial double bond character of the C-X bond and electronic repulsion. (Correct)