Given that triangle ABC is congruent to triangle DEF. If AC=11 m, ED=6 m, EF=15 m, ∠FDE=85
∘
and ∠ABC=55
∘
, then the perimeter of triangle ABC and ∠EFD are, respectively:

Since △ABC≅△DEF, their corresponding sides and angles are equal:
AB=DE=6 m

BC=EF=15 m

AC=DF=11 m

Perimeter of △ABC:

Perimeter=AB+BC+AC=6+15+11=32 m
For the angles:

∠CAB=∠FDE=85
∘


∠ABC=∠DEF=55
∘


In △DEF, the sum of angles is 180
∘
:

∠EFD=180
∘
−(∠FDE+∠DEF)
∠EFD=180
∘
−(85
∘
+55
∘
)=180
∘
−140
∘
=40
∘

Thus, the perimeter is 32 m and ∠EFD=40
∘
.