How many spherical balls each of $2\text{cm}$ radius can be made out of a solid metallic cube of edge $44\text{cm}$? (Take $\pi =\frac{22}{7}$)

Let the number of spherical balls that can be made be $n$.The volume of a solid metallic cube is given by:
$$\text{Volume of cube}=a^3$$
where $a=44\text{cm}$ is the edge of the cube.
$$\text{Volume of cube}=44\times 44\times 44{\text{cm}}^3$$
The volume of a single spherical ball is given by:
$$\text{Volume of sphere}=\frac{4}{3}\pi r^3$$
where $r=2\text{cm}$ is the radius of the ball.
$$\text{Volume of sphere}=\frac{4}{3}\times \frac{22}{7}\times 2^3=\frac{4}{3}\times \frac{22}{7}\times 8{\text{cm}}^3$$
Since the total volume remains conserved:
$$\text{Volume of cube}=n\times \text{Volume of single sphere}$$
$$44\times 44\times 44=n\times \frac{4}{3}\times \frac{22}{7}\times 8$$
Solving for $n$:
$$n=\frac{44\times 44\times 44\times 3\times 7}{4\times 22\times 8}$$
$$n=\frac{2\times 44\times 44\times 21}{32}$$
$$n=\frac{88\times 44\times 21}{32}$$
$$n=\frac{11\times 11\times 21}{1}=121\times 21=2541$$