Identify the correct reagents that would bring about the following transformation:

The transformation requires converting a terminal alkene to a terminal aldehyde with the same carbon count.Hydroboration-Oxidation: ${\text{BH}}_3$ followed by ${\text{H}}_2{\text{O}}_2/{\text{OH}}^{-}$ converts the alkene to a primary alcohol (${\text{R-CH}}_2{\text{CH}}_2\text{OH}$) following anti-Markovnikov rule.Selective Oxidation: $\text{PCC}$ (Pyridinium Chlorochromate) oxidizes the primary alcohol to an aldehyde (${\text{R-CH}}_2{\text{CH}}_2\text{CHO}$).Using ${\text{H}}_2\text{O}/{\text{H}}^{+}$ would give a secondary alcohol (Markovnikov). ${\text{KMnO}}_4$ would over-oxidize the alcohol to a carboxylic acid.