If $0<x<1$, then it is true that

For any real number $x$ in the interval $(0,1)$, multiplying the number by itself results in a smaller value (i.e., $x^2<x$). Therefore, as the exponent increases, the value of the expression decreases:
$$x^1>x^2>x^3>\cdots >x^{100}>x^{101}$$
Thus, $x^{100}>x^{101}$ is true.