If 12 students can read 4800 pages of a book in 15 days, then how many students can read 7200 pages of the same book in 10 days?
- A24
- B27
- C33
- D30
Solution & Step-by-step Explanation
Using the work-equivalence chain rule formula:
W
1
M
1
×D
1
=
W
2
M
2
×D
2
Where:
M
1
=12 students
D
1
=15 days
W
1
=4800 pages
M
2
=number of students required
D
2
=10 days
W
2
=7200 pages
Substituting the values into the formula:
4800
12×15
=
7200
M
2
×10
Simplifying the equation:
4800
180
=
7200
10M
2
480
18
=
7200
10M
2
80
3
=
7200
10M
2
10M
2
=
80
3×7200
10M
2
=3×90
10M
2
=270
M
2
=27
W
1
M
1
×D
1
=
W
2
M
2
×D
2
Where:
M
1
=12 students
D
1
=15 days
W
1
=4800 pages
M
2
=number of students required
D
2
=10 days
W
2
=7200 pages
Substituting the values into the formula:
4800
12×15
=
7200
M
2
×10
Simplifying the equation:
4800
180
=
7200
10M
2
480
18
=
7200
10M
2
80
3
=
7200
10M
2
10M
2
=
80
3×7200
10M
2
=3×90
10M
2
=270
M
2
=27