If 2Δ5=5, 2Δ3=3 and 8Δ4=16, then find the value of 16Δ8=?

Let's deduce the mathematical logic hidden behind the operator Δ:
Let the two numbers be A and B.

2Δ5→
2
2×5
​
=5

2Δ3→
2
2×3
​
=3

8Δ4→
2
8×4
​
=16

The relationship rule is clearly:

AΔB=
2
A×B
​

Applying this formula to evaluate 16Δ8:

16Δ8=
2
16×8
​
=16×4=64