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1 mark

If 2csc
2
A=x, then the value of x is:

  1. A
    secA−1
    secA

    +
    secA+1
    secA
  2. B
    secA−1
    cscA

    +
    secA+1
    cscA
  3. C
    cscA−1
    secA

    +
    cscA+1
    secA
  4. D
    cscA−1
    cscA

    +
    cscA+1
    cscA

Solution & Step-by-step Explanation

Let's simplify the expression in Option A:
Expression=
secA−1
secA

+
secA+1
secA


Take secA as a common factor:

secA(
secA−1
1

+
secA+1
1

)
Find a common denominator:

=secA(
(secA−1)(secA+1)
(secA+1)+(secA−1)

)
=secA(
sec
2
A−1
2secA

)
Using the identity sec
2
A−1=tan
2
A:

=
tan
2
A
2sec
2
A


Now convert secA and tanA into sinA and cosA:

=
cos
2
A
sin
2
A


2⋅
cos
2
A
1



=
sin
2
A
2

=2csc
2
A
This perfectly matches the given value x=2csc
2
A.

Practice this question

Try it yourself before checking the explanation above.

If 2csc
2
A=x, then the value of x is:
A
secA−1
secA

+
secA+1
secA
B
secA−1
cscA

+
secA+1
cscA
C
cscA−1
secA

+
cscA+1
secA
D
cscA−1
cscA

+
cscA+1
cscA

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