If 2x+2(4+3x)<2+3x>2x+x/2; then x can take which of the following values?
- A-3
- B1
- C0
- D-1
Solution & Step-by-step Explanation
The problem contains a double inequality system:
2x+2(4+3x)<2+3x
2+3x>2x+
2
x
Let's solve the first inequality:
2x+8+6x<2+3x
8x+8<2+3x
8x−3x<2−8
5x<−6
x<−
5
6
⟹x<−1.2
Now, let's solve the second inequality:
2+3x>2x+
2
x
2+3x>
2
5x
Multiply by 2:
4+6x>5x
6x−5x>−4
x>−4
Combining both results, the range of x is:
−4Let's test the given options against this range:
A) x=−3: Fits within (−4,−1.2)
B) x=1: Does not fit
C) x=0: Does not fit
D) x=−1: Does not fit
Hence, x=−3 is a valid value.
2x+2(4+3x)<2+3x
2+3x>2x+
2
x
Let's solve the first inequality:
2x+8+6x<2+3x
8x+8<2+3x
8x−3x<2−8
5x<−6
x<−
5
6
⟹x<−1.2
Now, let's solve the second inequality:
2+3x>2x+
2
x
2+3x>
2
5x
Multiply by 2:
4+6x>5x
6x−5x>−4
x>−4
Combining both results, the range of x is:
−4
A) x=−3: Fits within (−4,−1.2)
B) x=1: Does not fit
C) x=0: Does not fit
D) x=−1: Does not fit
Hence, x=−3 is a valid value.