If $30^{\text{th}}\text{ January 2003}$ was a Thursday, what was the day of the week on $2^{\text{nd}}\text{ March 2003}$?

Let's count the total number of remaining days between January 30, 2003, and March 2, 2003:
* Remaining days in January $=31-30=1\text{ day}$
* Days in February 2003 (2003 is a non-leap year) $=28\text{ days}$
* Days in March $=2\text{ days}$

$$\text{Total Days}=1+28+2=31\text{ days}$$

Now, find the number of odd days by dividing by 7:

$$\text{Odd Days}=31(\mathrm{mod}7)=3\text{ days}$$

Adding 3 days to Thursday:

$$\text{Thursday}+3\text{ days}=\text{Sunday}$$