If 42÷3+k×3−22÷11+4=28, then the value of k is:
- A0
- B1
- C4
- D2
Solution & Step-by-step Explanation
According to BODMAS rules, perform division first:
42÷3=14
22÷11=2
Now substitute these back into the equation:
14+k×3−2=28−4
14+3k−2=24
12+3k=24
3k=24−12
3k=12
k=4
42÷3=14
22÷11=2
Now substitute these back into the equation:
14+k×3−2=28−4
14+3k−2=24
12+3k=24
3k=24−12
3k=12
k=4