If 60% of (x−y) = 45% (x+y) and y=k% of x, then 49% of k is equal to:
- A7
- B5
- C9
- D6
Solution & Step-by-step Explanation
Given equation:
60% of (x−y)=45% of (x+y)
100
60
(x−y)=
100
45
(x+y)
60(x−y)=45(x+y)
Divide both sides by 15:
4(x−y)=3(x+y)
4x−4y=3x+3y
4x−3x=3y+4y
x=7y⟹y=
7
1
x
We are given y=k% of x:
y=
100
k
x
Comparing the two expressions for y:
100
k
=
7
1
⟹k=
7
100
Now, find 49% of k:
49% of k=
100
49
×
7
100
=7
60% of (x−y)=45% of (x+y)
100
60
(x−y)=
100
45
(x+y)
60(x−y)=45(x+y)
Divide both sides by 15:
4(x−y)=3(x+y)
4x−4y=3x+3y
4x−3x=3y+4y
x=7y⟹y=
7
1
x
We are given y=k% of x:
y=
100
k
x
Comparing the two expressions for y:
100
k
=
7
1
⟹k=
7
100
Now, find 49% of k:
49% of k=
100
49
×
7
100
=7