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If 60% of (x−y) = 45% (x+y) and y=k% of x, then 49% of k is equal to:

  1. A
    7
  2. B
    5
  3. C
    9
  4. D
    6

Solution & Step-by-step Explanation

Given equation:
60% of (x−y)=45% of (x+y)
100
60

(x−y)=
100
45

(x+y)
60(x−y)=45(x+y)
Divide both sides by 15:

4(x−y)=3(x+y)
4x−4y=3x+3y
4x−3x=3y+4y
x=7y⟹y=
7
1

x
We are given y=k% of x:

y=
100
k

x
Comparing the two expressions for y:

100
k

=
7
1

⟹k=
7
100


Now, find 49% of k:

49% of k=
100
49

×
7
100

=7

Practice this question

Try it yourself before checking the explanation above.

If 60% of (x−y) = 45% (x+y) and y=k% of x, then 49% of k is equal to:
A
7
B
5
C
9
D
6

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