If 6@1=12, 6@2=24 and 9@9=162, then find the value of 4@6=?
- A48
- B4
- C16
- D20
Solution & Step-by-step Explanation
Let's find the logic behind the operator @:
6@1→2×(6×1)=12
6@2→2×(6×2)=24
9@9→2×(9×9)=2×81=162
The pattern is:
a@b=2×(a×b)
Applying this rule to find 4@6:
4@6=2×(4×6)=2×24=48
6@1→2×(6×1)=12
6@2→2×(6×2)=24
9@9→2×(9×9)=2×81=162
The pattern is:
a@b=2×(a×b)
Applying this rule to find 4@6:
4@6=2×(4×6)=2×24=48