If $95474$ is written as $\text{GCBEB}$, then how is $73453$ written?

The coding follows a direct character-to-digit substitution cipher pattern extracted from the given example:
* $9\to \text{G}$
* $5\to \text{C}$
* $4\to \text{B}$
* $7\to \text{E}$

Using this established mapping for the number $73453$:

* $7\to \text{E}$
* $3\to \text{A}$ (by checking the remaining options starting with $\text{E}$)
* $4\to \text{B}$
* $5\to \text{C}$
* $3\to \text{A}$

Combining these letters gives $\text{EABCA}$.