If a cone of radius 10.5cm and height 12cm is melted and constructed into a cylinder of the same radius, what will be the height of this cylinder?
- A8 cm
- B1.33 cm
- C2 cm
- D4 cm
Solution & Step-by-step Explanation
When an object is melted and recast into another shape, its total volume remains constant.
Therefore,
Volume of Cylinder=Volume of Cone
The formula for the volume of a cone is:
V
cone
=
3
1
πr
1
2
h
1
The formula for the volume of a cylinder is:
V
cylinder
=πr
2
2
h
2
Given:
Radius of cone, r
1
=10.5cm
Height of cone, h
1
=12cm
Radius of cylinder, r
2
=10.5cm (same as cone, so r
1
=r
2
=r)
Let the height of cylinder be h
2
.
Equating the volumes:
πr
2
h
2
=
3
1
πr
2
h
1
Canceling πr
2
from both sides:
h
2
=
3
1
h
1
h
2
=
3
1
×12=4cm
Thus, the height of the cylinder is 4cm.
Therefore,
Volume of Cylinder=Volume of Cone
The formula for the volume of a cone is:
V
cone
=
3
1
πr
1
2
h
1
The formula for the volume of a cylinder is:
V
cylinder
=πr
2
2
h
2
Given:
Radius of cone, r
1
=10.5cm
Height of cone, h
1
=12cm
Radius of cylinder, r
2
=10.5cm (same as cone, so r
1
=r
2
=r)
Let the height of cylinder be h
2
.
Equating the volumes:
πr
2
h
2
=
3
1
πr
2
h
1
Canceling πr
2
from both sides:
h
2
=
3
1
h
1
h
2
=
3
1
×12=4cm
Thus, the height of the cylinder is 4cm.