If a cone of radius $3.5\text{cm}$ and height $9.6\text{cm}$ is melted and constructed into a cylinder of the same radius, what will be the height of this cylinder? (Take $\pi =\frac{22}{7}$)

When an object is melted and recast into another shape, its volume remains the same.Let the radius of the cone and cylinder be $r=3.5\text{cm}$.Let the height of the cone be $h_{\text{cone}}=9.6\text{cm}$.Let the height of the cylinder be $h_{\text{cylinder}}$.
$$\text{Volume of Cylinder}=\text{Volume of Cone}$$
$$\pi r^2{h}_{\text{cylinder}}=\frac{1}{3}\pi r^2{h}_{\text{cone}}$$
Since the radius $r$ is identical for both, we can cancel $\pi r^2$ from both sides:
$$h_{\text{cylinder}}=\frac{1}{3}{h}_{\text{cone}}$$
$$h_{\text{cylinder}}=\frac{1}{3}\times 9.6=3.2\text{cm}$$