If a man runs 6 kmph from his house, he misses the train at the station by 8 minutes . If he runs at 10 kmph , he reaches the station 7 minutes earlie - Quantitative Aptitude MCQ Competitive Exam 2026 | ExamTest.live

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If a man runs 6 kmph from his house, he misses the train at the station by 8 minutes . If he runs at 10 kmph, he reaches the station 7 minutes earlier than the departure of the train. What is the distance of the station from his house (in km)?

Solution & Step-by-step Explanation

Let the distance between the house and the station be d km . The time difference between arriving 8 minutes late and 7 minutes early is: Δ t = 8 - (- 7) = 15 minutes = \frac{15}{60} hours = \frac{1}{4} hour Using the time formula Time = \frac{Distance}{Speed} : \frac{d}{6} - \frac{d}{10} = \frac{1}{4} Taking the LCM of 6 and 10, which is 30 : \frac{5 d - 3 d}{30} = \frac{1}{4} \frac{2 d}{30} = \frac{1}{4} \frac{d}{15} = \frac{1}{4} d = \frac{15}{4} = 3 \frac{3}{4} km

Try it yourself before checking the explanation above.

If a man runs 6 kmph from his house, he misses the train at the station by 8 minutes . If he runs at 10 kmph, he reaches the station 7 minutes earlier than the departure of the train. What is the distance of the station from his house (in km)?

4 \frac{3}{4}

3 \frac{1}{2}

4 \frac{1}{4}

3 \frac{3}{4}

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