If ‘A’ stands for ‘+’, ‘B’ stands for ‘−’, ‘C’ stands for ‘×’ and ‘D’ stands for ‘÷’, what will come in place of the question mark (?) in the following equation?
$$29\text{ A }37\text{ B }14\text{ C }3\text{ A }(84\text{ D }4)\text{ A }46=\text{?}$$

Map the letters to their respective mathematical operators:
* $\text{A}\to +$
* $\text{B}\to -$
* $\text{C}\to \times$
* $\text{D}\to ÷$

Substitute these operators into the given equation:

$$29+37-14\times 3+(84÷4)+46$$

Solve step-by-step following the BODMAS rule:

1. Bracket: Evaluate $(84÷4)=21$

$$\text{Expression becomes: }29+37-14\times 3+21+46$$

2. Multiplication: Evaluate $14\times 3=42$

$$\text{Expression becomes: }29+37-42+21+46$$

3. Addition and Subtraction:

$$29+37=66$$

$$66-42=24$$

$$24+21=45$$

$$45+46=91$$

Hence, the answer is 91.